Get Programming in C C++

Tuesday, November 6, 2007

U may know ur date of birth but ur day of birth !!!

DATE ----------->>> DAY

Intro ::..

This program is used to find the day of a any given date... This may be your birthday or the day u met your first spouse or anything else.... This program is created with the last program as a base...

Source Code ::...

/*PROGRAM TO FIND THE DAY OF ANY DATE*/

#include stdio.h
#include conio.h

void main()
{
int x,i,d1=1,d2,m1=1,m2,y1=1,y2;
long int d=0,y=0;
clrscr();
printf("\n\n\n\n\n\n\n\n\n\n\tENTER THE DATE\n\n\t");
scanf("%d%d%d",&d2,&m2,&y2);
if(m2>12d2>31(m2==2&&((y2%4==0&&d2>29)(y2%4!=0&&d2>28))))
printf("\n\n\tInvalid date");
else
{
if(m1==m2&&y1==y2)
d=d2-d1;
else
{
d=31-d1;
d+=d2;
}
m1++;
while(m1=12&&y1!=y2)
{
m1=1;
y1++;
}
else
m1++;
}
d+=y;
i=d%7;
printf("\n\n\tThe day corresponding to the given date is\n\n\t\t");
switch(i)
{
case 6:
printf("SATURDAY");
break;
case 0:
printf("SUNDAY");
break;
case 1:
printf("MONDAY");
break;
case 2:
printf("TUESDAY");
break;
case 3:
printf("WEDNESDAY");
break;
case 4:
printf("THURSDAY");
break;
case 5:
printf("FRIDAY");
break;
}
}
getch();
}

Merits ::..

* This program too has no exceptional cases...U can know even the day when Buddha was born if u know the date....

Sample Output ::...

U can try this out by yourself by clicking the link below..... Its really interesting.....

http://www.ziddu.com/download.php?uid=aayel5yparCgl5ats6yZlJyiZbCWlJWr5
http://www.ziddu.com/download.php?uid=ba2hlJurb7GbmZettayZlJyiZ7CWlJWp7

Look out ::...

This program can be run on any normal C compilers...

Wednesday, October 10, 2007

Are u both really made for each other find out !!!

WHATS BETWEEN US YA ???

Intro ::....

This program is actually based on the fun game FLAMES i hope every one would have heard about it... If not follow me... In FLAMES

F - Friends

L - Love

A - Affection

M - Marriage

E - Enemy

S - Sister or in general any other relartion...

Its totally fun try it out in your system by copying this code.... In this program i have used the concept on circularly linked list from data structures a popular concept.... I have tried out this program with the repuisition of some of my friends... I hope u ll surely enjoy it.....

Source Code ::....

/*PROGRAM TO IMPLEMENT " FLAMES " */

#include stdio.h
#include string.h
#include alloc.h
#include conio.h

struct node
{
int data;
struct node *next;
}*head,*p,*old;

void main()
{
char s1[10],s2[10];
int i,j,k,l1,l2,l,s,c=0,g=0,opt;
clrscr();
printf("\n\n\n\n\tEnter the first string\n\t");
gets(s1);
l1=strlen(s1);
printf("\n\n\tEnter the second string\n\t");
gets(s2);
l2=strlen(s2);
for(i=0;i {

if(s1[i]==32)

g++;

for(j=0;j

{

if(s1[i]==s2[j]&&s1[i]!=32)

{

c+=2;

s=j;

for(k=j+1 k s2[s++]=s2[k];

j=l2;

}

for(i=0;i

if(s2[i]==32)

g++;

l=l1+l2-c-g;

head=(struct node *)malloc(sizeof(struct node));

head->data=1;
p=head;
for(i=2;i<=6;i++)

{

p->next=(struct node *)malloc(sizeof(struct node));
p=p->next;
p->data=i;
}
p->next=head;
p=head;
for(i=6;i>1;i--)
{
j=1;
while(j

old=p;

p=p->next;
j++;
}
old->next=p->next;
head=old->next;
p=head;
}
opt=head->data;
switch(opt)
{
case 1:
printf("\n\n\n\n\n\t\tLETS BETTER BE GOOD FRIENDS ");
break;
case 2:
printf("\n\n\n\n\n\t\tLOVE... AH... AH.. ");
break;
case 3:
printf("\n\n\n\n\n\t\tUH ONLY AN AFFECTION IT SEEMS ");
break;
case 4:
printf("\n\n\n\n\n\t\tENDS IN A MARRIAGE !!! ");
break;
case 5:
printf("\n\n\n\n\n\t\tYOU ARE MY FIRST ENEMY ");
break;
case 6:
printf("\n\n\n\t\tSOME HOW RELATED");
break;
}
getch();
}

Merits ::...

* Its totally fun and it no longer requires any manual calculation to enjoy it....
* It calculates exactly with or without the inclusion of initials....
* It helps one to understand the concepts related to circularly linked list...

Sample Output ::....

Enter the first name

JOSEPH

Enter the next name

STEPHEN

LETS BETTER BE GOOD FRIENDS...

Ull surely love experiencing this..... Want to know ur real relationship... Try this out by clicking the link below....

http://www.ziddu.com/download.php?uid=a7Gdl5iqa6%2BcnOKnZ6qhkZSrZKqal5uu7

http://www.ziddu.com/download.php?uid=ZKqcnJioaLKilpbzZaqZnJGlaaeZlZymaA%3D%3D3

Look out::....

Please do not take it seriously... Its just a fun game and nothing more than that....This program can be run on any C compiler as this is a C program... Your comments are always welcomed....

Friday, September 14, 2007

Make your data more secured !!!

PASSWORD PLEASE

Intro ::....

This program deals with the passwords.... U can know the entire details if u just compile them... This is just a sample program to just make u understand the basic concept.... U can use this program anywhere with some modifications as per ur necessity....

Source Code ::...

/*PROGRAM TO DEAL WITH PASSWORD*/

#include stdio.h
#include conio.h
#include process.h
#include ctype.h

FILE *fp;
int i,j,c[10],opt,pa;
char a[10]=" ",b[10]=" ";
void pass();

void main()
{
g:clrscr();
printf("\n\n\n\t\tENTER YOUR OPTION\n\n\n\n\t1.CHECK PASSWORD\n\n\n\t2.CHANGE PASSWORD\n\n\t");
scanf("%d",&opt);
switch(opt)
{
case 1:
{
fp=fopen("pass.txt","r");
fgets(b,20,fp);
fscanf(fp,"%d",&i);
fclose(fp);
pa=i;
clrscr();
printf("\n\n\n\tPASSWORD PLEASE\n\n\n\t");
for(i=0;i<=20;i++)
{
a[i]=getch();
c[i]=toascii(a[i]);
if(c[i]==13)
{
pass();
exit(0);
}
else
printf("*");
}
}
case 2:
{
clrscr();
printf("\n\n\n\n\tENTER YOUR NEW PASSWORD\n\n\t");
for(i=0;i<=20;i++)
{
b[i]=getch();
c[i]=toascii(b[i]);
if(c[i]==13)
{
fp=fopen("pass.txt","w+");
fprintf(fp,"%s\n%d",b,i);
fclose(fp); goto g;
}
else printf("*");
}
}
}
}

void pass()
{
int k=0;
for(j=0;j<=i;j++)
{
if(a[j]==b[j])
k++;
}
if(pa==i&&k==pa)
printf("\n\n\n\n\n\t\tWELCOME U HAVE ENTERED THE RIGHT PASSWORD");
else
printf("\n\n\n\n\n\n\t\tCHECK YOUR PASSWORD");
getch();
}

Merits ::...

* This program is very helpful as this can be attached with any of ur other programs to improve ur security....
* I personally didnt find any exceptional cases here...
* U can set ur password to any number of digits as passwords... It may contain alphabets digits or numbers...

Sample Output ::....